已知数列{a_n}满足:a₁=1,a₂=2,2a_n=a_n-1+a_n+1(n≥2,n∈N^*),数列{b_n}满足b₁=2,a_nb_n+1=2a_n+1b_n.
(1)求数列{a_n}的通项a_n;
(2)求证:数列为等比数列,并求数列{b_n}的通项公式.